#If it's a subfolder, recursively call rename files on that directory. New_name = base_directory + '/' + directory_name + '.' + split_name(path) #If the path points to a file, rename it directory name + '.' + extension #Get the folder name for base_directory (c:\users\foobar => foobar)ĭirectory_name = os.basename(base_directory) WARNING! You will be very sad if you have multiple files with the same extension in any of those folders
MASS RENAME FILES BASED ON FOLDER NAME PLUS
Recursively renames files in subdirectories of base_directory so each file is named the subdirectory name plus the extension Given a file name, returns a pair with the name and extension (hello.txt => ) Python is a good choice here because it has such friendly syntax.Ī extremely simple script that will solve your problem might look like this import os You could use almost any programming language (probably including R) to do this.
MASS RENAME FILES BASED ON FOLDER NAME FULL
To be sure the code will not fail, it is necessary to iterate over the files, renaming each one for /d %%a in ("c:\.\Raptors\*") do for %%b in ("%%~fa\*") do ren "%%~fb" "%%~nxa%%~xb"įor each folder ( %%a), for each file inside the folder ( %%b), rename the file to the name of full folder name ( %%~nxa) with the extension of the file ( %%~xb) Rename in File Explorer To rename multiple files from File Explorer, select all the files you wish to rename, then press the F2 key.
While the basic idea of using only one ren command to rename all the files under each folder is probably the fastest way, the way ren command handles wildcards makes this code fail if the folder name contains dots. The code in the do clause executes a ren command, for all the files under the subfolder ( %%~fa is the folder being processed with full path), changing its name to the name of the folder ( %%~na).Įdited The answer is not completely correct. For each of the folders, the replaceable parameter %%a will hold a reference to the subfolder and the code in the do clause is executed for each one. You can contact Ajmal Abbasi for Consultancy, Technical Assistance and Technical Discussions.For /d %%a in ("c:\.\Raptors\*") do ren "%%~fa\*.*" "%%~na.*"įor each folder inside the parent one, rename all the files inside the folder to the name of the folder but keeping the extensionįor command is used to iterate over the list of folders ( /d) under the parent folder. He has worked on a number of highly critical integration projects in various sectors by using his skills in TIBCO Flogo, TIBCO API Management (Mashery), TCI, Tibco Designer, TIBCO Business Studio, Adapters, TIBCO EMS, RV, Administrator, TIBCO BE, TIBCO ActiveSpaces etc.Ījmal Abbasi has experience with MuleSoft ESB as well.Ījmal Abbasi is also experienced in the area of API Management particularly with WSO2 API management platforms.Ījmal Abbasi is also experienced in developing solutions using Core Java and J2EE Technologies. He has extensive practical knowledge of TIBCO Business Works, TIBCO Cloud, TIBCO Flogo, TIBCO Mashery, TIBCO Spotfire, EMS and TIBCO ActiveSpaces. as shown in below screenshot:Ījmal Hussain Abbasi is Integration Consultant By Profession with 12+ years experience in Integration domain mainly with TIBCO products. Now, If we go to the folder (D:\files\), we can see that all the four files have been renamed by replacing _ with. Im looking to rename a large number of files based on the folder name in which the file resides. ).Īfter executing the above code in Netbeans IDE, I got below result stating that all the four files in the given directory have been renamed successfully: It uses second string as a search criteria and replaces it with the third string (in this case second string is _ and third string is. The above Java Class has one public method that is taking a folder name and two other strings as input. To read the content of a text file, use the Read text from file action. To append text content or overwrite text files, deploy the Write text to file action. String result= rn.renameBulk("D:\\files\\", "_", ".") For example, the Rename file (s) action includes options to set a new name or add, replace or remove a text string to the existing file name.
Return "Successfully renamed "+filesList.length+" files." String newName= (filesList.toString().replaceAll(ReplaceFrom, ReplaceWith)) įilesList.renameTo(new File(newName)) This method will rename all files in a folder by chaning ReplaceFrom string with ReplaceWith string Public String renameBulk (String folderName, String ReplaceFrom, String ReplaceWith) Folder contents as of now are shown below:īelow is the Java Code that I have written for renaming all the files in this folder by replacing _ with.
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